9x-7i > 3(3x-7u)=

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9x-7i > 3(3x-7u)=

Post by blivvy on Sun May 08, 2011 5:47 am

?

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Re: 9x-7i > 3(3x-7u)=

Post by Mr.Fjord on Sun May 08, 2011 9:56 am

Hmmm...Divide the eight....add the one....carry the two...Fourty two!

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Re: 9x-7i > 3(3x-7u)=

Post by blivvy on Sun May 08, 2011 10:20 am

wrong

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Re: 9x-7i > 3(3x-7u)=

Post by Loki on Sun May 08, 2011 11:28 am

Love you too, blivvy <3

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Re: 9x-7i > 3(3x-7u)=

Post by Wonko the Sane on Sun May 08, 2011 11:32 am

9x-7i > 3(3x-7u) = ?

3(3x-7u) < 9x-7i = ?

1 < 3, so

1(1x-7u) < 9x-7i = ?

which means:

-7u < 9x-7i = ?

-7u is clearly less than whatever the rest is, so we can just get rid of that now:

9x-7i = ?

9x = 7i

x = 7i / 9

Everyone knows that imaginary numbers are figments of some deranged mathematician's imagination, so there's no harm in just ignoring them completely. Since 7 times an imaginary number is still an imaginary number:

x = 1/9
QED (quite easily done)

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Re: 9x-7i > 3(3x-7u)=

Post by blivvy on Sun May 08, 2011 12:01 pm

Loki wrote:Love you too, blivvy <3

Heh but u didn't give any answer Rolling Eyes

Wonko the Sane wrote:9x-7i > 3(3x-7u) = ?

3(3x-7u) < 9x-7i = ?

1 < 3, so

1(1x-7u) < 9x-7i = ?

which means:

-7u < 9x-7i = ?

-7u is clearly less than whatever the rest is, so we can just get rid of that now:

9x-7i = ?

9x = 7i

x = 7i / 9

Everyone knows that imaginary numbers are figments of some deranged mathematician's imagination, so there's no harm in just ignoring them completely. Since 7 times an imaginary number is still an imaginary number:

x = 1/9
QED (quite easily done)

Eh yea idk. I suck at algebra. But you get an A+++ if you are right Smile

Anyway the answer I was looking for was (before loki ruined it) i <3 u.

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Re: 9x-7i > 3(3x-7u)=

Post by Loki on Sun May 08, 2011 12:19 pm

I just wanted to show that I knew the answer but still give others a chance to try too Sad

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Re: 9x-7i > 3(3x-7u)=

Post by blivvy on Sun May 08, 2011 12:29 pm

Lol. Is i <3 u really the answer tho?

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Re: 9x-7i > 3(3x-7u)=

Post by Loki on Sun May 08, 2011 1:42 pm

i < 3u Yeah.

9x - 7i < 3 (3x -7u)
= 9x - 7i < 9x - 21u
= -7i < -21u (canceling out the 9x)
Simplified: i < 3u
Therefore: I love you. It's a pretty nerdy chatup line that I found years ago Very Happy

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Re: 9x-7i > 3(3x-7u)=

Post by Theicecreaman on Sun May 08, 2011 1:56 pm

Mr.Fjord wrote:Hmmm...Divide the eight....add the one....carry the two...Fourty two!
cheers Best proof ever.

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Re: 9x-7i > 3(3x-7u)=

Post by KaiStagon on Sun May 08, 2011 5:49 pm

Wonko the Sane wrote:
QED (quite easily done)

I don't think that's what that is Razz Razz

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Re: 9x-7i > 3(3x-7u)=

Post by Mr.Fjord on Sun May 08, 2011 6:23 pm

KaiStagon wrote:
Wonko the Sane wrote:
QED (quite easily done)

I don't think that's what that is Razz Razz

I'm pretty sure it's foreign for as was demonstrated.

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Re: 9x-7i > 3(3x-7u)=

Post by Theicecreaman on Sun May 08, 2011 9:20 pm

Quick
Erratic
Ducklings


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Re: 9x-7i > 3(3x-7u)=

Post by Loki on Sun May 08, 2011 11:35 pm

Quick
Efficient
Drooling

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Re: 9x-7i > 3(3x-7u)=

Post by Wonko the Sane on Mon May 09, 2011 12:54 am

Listen people, as a twice graduated alumni of the fine arts association of disassociated mathematics haters and regressive physical disproofs by law of denaturing the pudding until sanity happens, I think I know a thing or two about proofs and how to quite easily do them.

I'm ready for question number two!

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